将十进制转换为R进制

帮朋友做的一个作业，要求用栈实现，快两年没写过Java啦！

 

import java.util.*;
import java.io.*;
public class NToR {

    public static void main(String[] args) {
        
        int n=0;
        int m=0;
        try
        {
            InputStreamReader isr=new InputStreamReader(System.in);
            BufferedReader result=new BufferedReader(isr);
            System.out.print("请输入你要转化的十进制数：");
            String s1 = result.readLine();
            n=Integer.parseInt(s1);
            System.out.print("请问你需要把它转化为多少进制(2~32)：");
            String s2 = result.readLine();
            m=Integer.parseInt(s2);
        }
        catch (Exception e) {
            System.out.println("读取数据失败！");
        }

        cover_to (n,m);
    }
    
    public static void cover_to(int num,int base){
        
        int t = num;
        int r = 0;
        int n = 0;
        Stack re=new Stack();

        if (base < 2 || base > 32)
        {
            System.out.println("所输入的进制数非法！");
            return;
        }
               

        while((n = t/base) != t) {
         
                r = t%base;
                t = n;
                
                if(r > 9)
                    re.push((char)('A'+(r-10)));
                else
                    re.push((char)('0'+r));
        }
        System.out.print("转化结果为：");
        while(!re.isEmpty()){
            System.out .print(re.pop());
        }
    }
}