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全部博文(594)
分类: C/C++
2019-04-25 17:29:29
平台:x86_64
结论:Zset的最大分数不要超过18014398509481982(17位数字,54位二进制),否则不会得到期望的值。
REdis:5.0.4
Zset采用double存储分数值(score),而incrbyfloat和hincrbyfloat采用的是long double存储数值。
double本身是可以存储比18014398509481982(17位数字,54位二进制)大的值,比如18014398509481983(也是17位数字,54位二进制)。但REdis在返回结果时,调用strtod将值转成double类型。
取值源代码:
double zzlGetScore(unsigned char *sptr) { // t_zset.c:722 unsigned char *vstr; unsigned int vlen; long long vlong; char buf[128]; double score;
serverAssert(sptr != NULL); serverAssert(ziplistGet(sptr,&vstr,&vlen,&vlong));
if (vstr) { memcpy(buf,vstr,vlen); buf[vlen] = '\0'; // 调用库函数strtod, // 如果值小于18014398509481983,能得到预期的值, // 否则总是返回18014398509481984(2的54次方)。 score = strtod(buf,NULL); // 字符串转double } else { score = vlong; }
return score; } |
以字符串形式返回:
/* Add a double as a bulk reply */ void addReplyDouble(client *c, double d) { // networking.c:471 char dbuf[128], sbuf[128]; int dlen, slen; if (isinf(d)) { /* Libc in odd systems (Hi Solaris!) will format infinite in a * different way, so better to handle it in an explicit way. */ addReplyBulkCString(c, d > 0 ? "inf" : "-inf"); } else { dlen = snprintf(dbuf,sizeof(dbuf),"%.17g",d); // double转字符串 slen = snprintf(sbuf,sizeof(sbuf),"$%d\r\n%s\r\n",dlen,dbuf); addReplyString(c,sbuf,slen); } } |
x86_64上的测试:
127.0.0.1:6379> del k1 (integer) 1 127.0.0.1:6379> zadd k1 18014398509481982 m1 (integer) 1 127.0.0.1:6379> zrange k1 0 -1 WITHSCORES 1) "m1" 2) "18014398509481982" 预期的值 127.0.0.1:6379> del k1 (integer) 1 127.0.0.1:6379> zadd k1 18014398509481983 m1 (integer) 1 127.0.0.1:6379> zrange k1 0 -1 WITHSCORES 1) "m1" 2) "18014398509481984" 非预期的值(和strtod相关)
127.0.0.1:6379> del k1 (integer) 1 127.0.0.1:6379> zadd k1 18014398509481982 m1 (integer) 1 127.0.0.1:6379> zrange k1 0 -1 WITHSCORES 1) "m1" 2) "18014398509481982" 预期的值 127.0.0.1:6379> zincrby k1 1 m1 "18014398509481984" 非预期的值 127.0.0.1:6379> zrange k1 0 -1 WITHSCORES 1) "m1" 2) "18014398509481984" 非预期的值 |
附:C/C++浮点知识图谱