有一道练习题:输入某年某月某日,判断这一天是这一年的第几天?看到这个题,我想到了,这个月以前的天数加上这个月的天数,即可完成。然后根据年份,判断是否闰月,来判断2月份的天数代码如下:
#include <stdio.h>
int main(int arc,char *argv[]) { int year,month,day; int sum = 0; int leap,error=0; printf("please intput year,month,day?"); scanf("%d,%d,%d",&year,&month,&day); switch(month) { case 1: sum = 0; break; case 2: sum = 31; break; case 3: sum = 31 + 28; break; case 4: sum = 31 + 28 + 31; break; case 5: sum = 31 + 28 + 31 + 30; break; case 6: sum = 31 + 28 + 31 + 30 + 31; break; case 7: sum = 31 + 28 + 31 + 30 + 31 + 30; break; case 8: sum = 31 + 28 + 31 + 30 + 31 + 30 + 31; break; case 9: sum = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31; break; case 10: sum = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30; break; case 11: sum = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31; break; case 12: sum = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30; break; default: printf("month is error,please check it."); error = 1; break; } if (error != 1) { sum += day; if ((year % 100 == 0 && year % 400 == 0 ) || (year % 4 == 0 && year % 100 != 0)) { leap = 1; } else { leap = 0; } if (leap == 1 && month > 2) { sum += 1; } printf("it is the %d day in year.",sum); } system("pause"); return 1; }
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