分类:
2011-03-15 08:28:54
2,栈的动态数组实现
struct stack_record {
int maxlen; //栈最大的深度
int sp; //栈顶指针
int *arr; //栈体
};
typedef struct stack_record Stack;
Stack *create(int max_num)
{
Stack *ss;
ss = (Stack *)malloc(sizeof(Stack));
if (!ss) {
return NULL;
}
ss->arr = (int *)malloc(max_num*sizeof(int));
if (!ss->arr)
return NULL;
ss->sp = 0; //表示空栈
ss->maxlen = max_num;
return ss;
}
int push(Stack *s, int val)
{
assert(s && s->arr);
if (s->sp < s->maxlen) {
s->arr[s->sp++] = val;
return 0;
} else {
printf("error: stack full!\n");
return -1;
}
}
int pop(Stack *s)
{
assert(s && s->arr);
if (s->sp > 0) { //必须>0,若=0,表示空栈
return s->arr[--s->sp];
} else {
return -1;
}
}
void print_stack(Stack *s)
{
assert(s && s->arr);
int i;
for (i = 0; i < s->sp; i++) {
printf("%d ", s->arr[i]);
}
}
//测试例程
#define MAXLEN 20
int main(void)
{
char a[MAXLEN] = {'\0'};
Stack *s;
char *p;
int v;
fgets(a, MAXLEN, stdin);
a[strlen(a)-1] = '\0';
printf("a=[%s]\n", a);
s = create(MAXLEN);
if (!s) {
printf("create stack error!\n");
return 1;
}
p = a;
while ('\0' != *p) {
push(s, *p);
p++;
}
printf("\n-----pop-----\n");
while (-1 != (v=pop(s))) {
printf("%c ", v);
}
printf("\nend\n");
return 0;
}
3, 栈的链表实现
/*
* 栈的链表实现
* 其算法思想是:
* 压栈:从链表的头指针添加结点
* 出栈:从链表的头结点删除结点,并弹出该结点的值
*
*/
#include "all.h"
struct node {
int data;
struct node *next;
};
typedef struct node Stack;
/*
* 创建一个栈 : 实际上是创建一个链表的头结点
*/
Stack *creat_stack(void)
{
Stack *s;
s = (Stack *)malloc(sizeof(Stack));
if (!s) {
fprintf(stderr, "malloc error!\n");
return NULL;
}
s->next = NULL;
return s;
}
int is_empty(Stack *s)
{
return s->next == NULL;
}
/*
* 从链表的头部插入来实现压栈
*/
void push(Stack *s, int val)
{
struct node *node;
node = (struct node *)malloc(sizeof(struct node));
if (!node) {
fprintf(stderr, "malloc error!\n");
return ;
}
node->data = val;
node->next = s->next; //从链表头部插入
s->next = node;
}
/*
* 返回链表的第一个元素:出栈
*/
int pop(Stack *s)
{
Stack *sp;
int val;
if (is_empty(s)) //空栈
return -1;
sp = s->next;
s->next = s->next->next;
val = sp->data;
free(sp);
return val;
}
//测试例程
#define MAXLEN 20
int main(void)
{
char a[MAXLEN] = {'\0'};
Stack *s;
char *p;
int v;
fgets(a, MAXLEN, stdin);
a[strlen(a)-1] = '\0';
printf("a=[%s]\n", a);
s = creat_stack();
if (!s) {
printf("create stack error!\n");
return 1;
}
p = a;
while ('\0' != *p) {
push(s, *p);
p++;
}
printf("\n-----pop-----\n");
while (-1 != (v=pop(s))) {
printf("%c ", v);
}
printf("\nend\n");
return 0;
}
4,栈的应用