ACM UVA 10300 (Ecological Premium)

题目： 

思路： 简单题

代码：

//
// Author: xfye
// Status: AC
//

#include <iostream>

using namespace std;

int main()
{
    int cases = 0;
    cin >> cases;

    for (int i = 0; i < cases; i++) {
        int farmerNum = 0;
        cin >> farmerNum;
        int result = 0;
        for (int j = 0; j < farmerNum; j++) {
            int yardSize = 0;
            int animalsNum = 0;
            int friendliness = 0;
            cin >> yardSize >> animalsNum >> friendliness;
            result += (yardSize * friendliness);
        }

        cout << result << endl;
    }

    return 0;
}