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分类: 系统运维

2010-10-17 23:15:04

Smv Message analysis
kevin 2010-10-17
------------------------------------------------------------------
0000   01 0c cd 01 22 12 00 0c cd 01 22 19 88 ba 10 28
0010   00 77 00 00 00 00 60 6d 80 01 01 a2 68 30 66 80
0020   15 4c 4e 31 31 30 32 5f 4d 55 31 5f 35 38 31 30
0030   4d 55 6e 6e 30 32 82 02 08 0d 83 04 00 00 00 01
0040   85 01 00 87 40 ff ff f0 40 00 00 00 00 ff ff 7a
0050   40 00 00 00 00 ff ff 9b b0 00 00 00 00 ff ff 8a
0060   f8 00 00 00 00 ff ff 7a 40 00 00 00 00 ff ff f5
0070   38 00 00 00 00 ff ff f6 91 00 00 00 00 ff ff f5
0080   38 00 00 00 00

参照标准9-2解析
------------------------------------------------------------------
01 0c cd 01 22 12  //Destination Address: 01:0c:cd:01:22:12
00 0c cd 01 22 19  //     Source Address: 00:0c:cd:01:22:19
88 ba              //               Type: IEC 61850/SV (Sampled Value Transmission (0x88ba)
10 28              //              APPID: 0x1028
00 77              //             Length: 119
00 00              //         Reserved 1: 0x0000
00 00              //         Reserved 2: 0x0000
60 6d              //                Tag:0x60(savPdu),Len:0x6d
80 01              //                Tag:0x80(noASDU),Len:0x01
01                 //             noASDU: 1
a2 68              //                Tag:0xa2(seqASDU),Len:0x68
30 66             //                Tag:0x30(item1),Len:0x66
80 15                 //                Tag:0x80(svID),Len:0x15
4c 4e 31 31 30 32 5f  //               svID: LN1102_MU1_5810MUnn02
4d 55 31 5f 35 38 31  //               svID: ---
30 4d 55 6e 6e 30 32  //               svID: ---
82 02              //                Tag:0x82(smpCnt),Len:0x02
08 0d              //             smpCnt: 2061
83 04              //                Tag:0x83(confRef),Len:0x04
00 00 00 01        //            confRef: 1
85 01              //                Tag:0x85(smpSynch),Len:0x01
00                 //           smpSynch: none (0)
87 40              //                Tag:0x87(Sequence of Data),Len:0x40
ff ff f0 40 00 00 00 00 //     sample1  value:  -4032  quality: 0x00000000, validity: good, source: process
ff ff 7a 40 00 00 00 00 //     sample2  value: -34240  quality: 0x00000000, validity: good, source: process
ff ff 9b b0 00 00 00 00 //     sample3  value: -25680  quality: 0x00000000, validity: good, source: process
ff ff 8a f8 00 00 00 00 //     sample4  value: -29960  quality: 0x00000000, validity: good, source: process
ff ff 7a 40 00 00 00 00 //     sample5  value: -34240  quality: 0x00000000, validity: good, source: process
ff ff f5 38 00 00 00 00 //     sample6  value:  -2760  quality: 0x00000000, validity: good, source: process
ff ff f6 91 00 00 00 00 //     sample7  value:  -2415  quality: 0x00000000, validity: good, source: process
ff ff f5 38 00 00 00 00 //     sample8  value:  -2760  quality: 0x00000000, validity: good, source: process
       
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给主人留下些什么吧!~~

xurichusheng2013-08-13 15:45:27

svID: LN1102_MU1_5810MUnn02
这个是怎么得到的?

chenst112012-03-07 17:09:51

你怎么知道sample后面应该这样解析呢?

chinaunix网友2010-10-18 16:49:36

很好的, 收藏了 推荐一个博客,提供很多免费软件编程电子书下载: http://free-ebooks.appspot.com