高效 python (2)

一个班的学生姓名和成绩如下，打印出及格学生的姓名及成绩：

A	B	C	D	E	F	G
67	41	88	99	65	55	27

C:

#include <stdio.h>

typedef struct {
        char name[255];
        int score;
} testInfoT;

int main()
{
        testInfoT ti[] = {
                {"A", 67},
                {"B", 41},
                {"C", 88},
                {"D", 99},
                {"E", 65},
                {"F", 55},
                {"G", 27},
        };

        for (int i = 0; i < sizeof(ti) / sizeof(testInfoT); i++){
                if (ti[i].score > 60){
                        printf("%s:%d\n", ti[i].name, ti[i].score);
                }
        }

        return 0;
}

python:

testInfo = {
        "A":67, \
        "B":41, \
        "C":88, \
        "D":99, \
        "E":65, \
        "F":55, \
        "G":27}

print(filter(lambda x : x[1] > 60, testInfo.items()))

filter(function, sequence)：对sequence中的item依次执行function(item)，将执行结果为True的item组成一个List/String/Tuple（取决于sequence的类型）返回.