分类： C/C++
2012-11-19 10:55:42
When you call exit(), the destructors of automatic objects (local variables) do not get called.
In your specific example, the std::string destructor is not called, so the memory owned by thestd::string is never deallocated.
The reason there is no leak if you have fail() take a const char* is that there is no destructor forconst char*; nothing is deallocated when a pointer is destroyed. If the pointer points to dynamically allocated memory, then that memory must be deallocated (by you) before the program exits, otherwise you have a memory leak. If it points to a string literal, then there is no memory leak because string literals have static storage duration (that is, they exist for the entire lifetime of your program).
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