最近突然有必要测试C语言中各个函数的运行时间,于是就搜索了一下,发现有4种方法可以达成测算程序运行时间的目的。
它们分别是使用clock, times, gettimeofday, getrusage来实现的。下面就来逐一介绍,并比较它们的优劣点。
系统测试环境:
VirtualBox (Ubuntu 9.10)
gcc version 4.4.1
libc6 2.10.1-0ubuntu16
Core Duo T2500 2GMHz
首先先贴出我测试用的程序吧。
程序做的处理很简单,就是填写一个1024*1024的矩阵。
只要修改第11行的定义值,就可以使用不同的测量方法了。
- #include <sys/time.h>
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#include <sys/resource.h>
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#include <unistd.h>
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#include <stdio.h>
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#include <time.h>
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#define TEST_BY_CLOCK (char)(0x00)
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#define TEST_BY_TIMES (char)(0x01)
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#define TEST_BY_GETTIMEOFDAY (char)(0x02)
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#define TEST_BY_GETRUSAGE (char)(0x03)
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#define TEST_METHOD (TEST_BY_GETTIMEOFDAY)
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#define COORDINATION_X (int)(1024)
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#define COORDINATION_Y (int)(1024)
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static int g_Matrix[COORDINATION_X][COORDINATION_Y];
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double getTimeval()
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{
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struct rusage stRusage;
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struct timeval stTimeval;
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if (TEST_METHOD == TEST_BY_GETTIMEOFDAY) {
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gettimeofday(&stTimeval, NULL);
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} else if (TEST_METHOD == TEST_BY_GETRUSAGE) {
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getrusage(RUSAGE_SELF, &stRusage);
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stTimeval = stRusage.ru_utime;
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}
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return stTimeval.tv_sec + (double)stTimeval.tv_usec*1E-6;
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}
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int main()
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{
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int i, j;
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int n = 0;
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clock_t clockT1, clockT2;
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double doubleT1, doubleT2;
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if (TEST_METHOD == TEST_BY_CLOCK) {
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clockT1 = clock();
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} else if (TEST_METHOD == TEST_BY_TIMES) {
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times(&clockT1);
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} else if (TEST_METHOD == TEST_BY_GETTIMEOFDAY) {
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doubleT1 = getTimeval();
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} else if (TEST_METHOD == TEST_BY_GETRUSAGE) {
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doubleT1 = getTimeval();
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}
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for (i = 0; i < COORDINATION_X; i++) {
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for (j = 0; j < COORDINATION_Y; j++) {
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g_Matrix[i][j] = i * j;
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}
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}
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if (TEST_METHOD == TEST_BY_CLOCK) {
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clockT2 = clock();
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printf("Time result tested by clock = %10.30f\n",
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(double)(clockT2 - clockT1)/CLOCKS_PER_SEC);
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} else if (TEST_METHOD == TEST_BY_TIMES) {
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times(&clockT2);
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printf("Time result tested by times = %10.30f\n",
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(double)(clockT2 - clockT1)/sysconf(_SC_CLK_TCK));
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} else if (TEST_METHOD == TEST_BY_GETTIMEOFDAY) {
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doubleT2 = getTimeval();
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printf("Time result tested by gettimeofday = %10.30f\n",
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(double)(doubleT2 - doubleT1));
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} else if (TEST_METHOD == TEST_BY_GETRUSAGE) {
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doubleT2 = getTimeval();
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printf("Time result tested by getrusage = %10.70f\n",
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(double)(doubleT2 - doubleT1));
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}
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return 0;
- }