awk 日期格式 与 提取

给定的时间区间提取目标行

start="2011 09 07 09 30 00"

end="2011 09 07 10 00 59"

awk '$1~/ERROR/{ print $0} ' catalina.out | awk -F '[-: ]+' -v s="$start" -v  e="$end" 'mktime($2" "$3" "$4" "$5" "$6" "substr($7,1,2))>=mktime(s)&&mktime($2" "$3" "$4" "$5" "$6" "substr($7,1,2))<=mktime(e)'

提取时间段--------------搞了很久在别人提醒下，直蛋疼.....................

 

#!/bin/bash
start="2011 09 07 09 30 00" end="2011 09 07 10 00 59"
awk -F '[-: ]+' -v s="$start"  '{ if ( $1~/ERROR/ && mktime($2" "$3" "$4" "$5" "$6" "substr($7,1,2))
>=mktime(s)) print NR }' catalina.out  > tmp1
awk -F '[-: ]+' -v e="$end"  '{ if ( $1~/ERROR/ && mktime(e)>=mktime($2" "$3" "$4" "$5" "$6"
"substr($7,1,2)))  print NR }' catalina.out  > tmp2
t1=`head -n 1  tmp1`t2=`tail  -n 1  tmp2`
sed -n ''$t1','$t2'p' catalina.outrm -rm tmp1rm -rm tmp2