Chinaunix首页 | 论坛 | 博客
  • 博客访问: 1958589
  • 博文数量: 261
  • 博客积分: 8073
  • 博客等级: 中将
  • 技术积分: 2363
  • 用 户 组: 普通用户
  • 注册时间: 2006-04-10 15:23
文章分类

全部博文(261)

文章存档

2013年(1)

2012年(1)

2011年(50)

2010年(34)

2009年(4)

2008年(17)

2007年(55)

2006年(99)

分类:

2007-06-14 10:41:08

题目

Financial Management
Time Limit:1000MS  Memory Limit:10000K
Total Submit:24814 Accepted:11736

Description
Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has decided that he needs to grab hold of his financial portfolio and solve his financing problems. The first step is to figure out what's been going on with his money. Larry has his bank account statements and wants to see how much money he has. Help Larry by writing a program to take his closing balance from each of the past twelve months and calculate his average account balance.

Input
The input will be twelve lines. Each line will contain the closing balance of his bank account for a particular month. Each number will be positive and displayed to the penny. No dollar sign will be included.

Output
The output will be a single number, the average (mean) of the closing balances for the twelve months. It will be rounded to the nearest penny, preceded immediately by a dollar sign, and followed by the end-of-line. There will be no other spaces or characters in the output.

Sample Input

100.00
489.12
12454.12
1234.10
823.05
109.20
5.27
1542.25
839.18
83.99
1295.01
1.75

Sample Output

$1581.42

程序

#include 

int main()
{
        int i;
        float account, tmp;
        for(account = 0,i = 0;i < 12;i++){
                scanf("%f", &tmp);
                account += tmp;
        }
        printf("$%.2f\n", account/12);
}

结果

Run ID User Problem Result Memory Time Language Code Length Submit Time
2267375 Accepted 56K 0MS 249B 2007-06-14 10:39:06

阅读(1753) | 评论(0) | 转发(0) |
给主人留下些什么吧!~~