**原创内容, 转载请注明
接受的srt字幕时间格式: 00:00:00,000 --> 00:00:00,000
不过接近0秒的地方往回调时会不会出错还没有测试,估计是得手动去掉不对的行,不过不影响观看.
module Main where
import Text.Parsec
import Text.Parsec.Prim
import Text.Parsec.Language
import qualified Text.Parsec.Token as P
import Control.Applicative hiding ((<|>))
import Text.Printf
import System.Environment
lxr = P.makeTokenParser emptyDef
integer = P.integer lxr
colon = P.colon lxr
symbol = P.symbol lxr
comma = P.comma lxr
data TT = TT Integer Integer Integer Integer Integer Integer Integer Integer
| TX
instance Show TT where
show (TT a b c d e f g h) =
printf "%02u:%02u:%02u,%03u --> %02u:%02u:%02u,%03u" a b c d e f g h
timeLine =
try (TT <$> integer <* colon
<*> integer <* colon
<*> integer <* comma
<*> integer
<* symbol "-->"
<*> integer <* colon
<*> integer <* colon
<*> integer <* comma
<*> integer)
<|> return TX
main :: IO ()
main = do
{ args <- System.Environment.getArgs
; if args == [] then
do { putStrLn "<(C)WuXingbo> Usage: SrtShift.exe '<' in.srt '>' out.srt"
; putStrLn " :: 1000 : delay 1000ms"
; putStrLn " -1000 : forward 1000ms"
; putStrLn " redirect STDIN/STDOUT"
; return ()
}
else
do {
; let a = head args
; let i = read a :: Integer
; interact $ shiftSrt i
; return ()
}
}
shiftSrt :: Integer -> String -> String
shiftSrt i ss = unlines $ map (tryShift i) (lines ss)
tryShift :: Integer -> String -> String
tryShift i s =
case parse timeLine [] s of
Right t@(TT a b c d e f g h) ->
show $ shiftTime t i
_ -> s
shiftTime :: TT -> Integer -> TT
shiftTime (TT a b c d e f g h) i =
let (cd, d') = fullAdd 1000 (d, i)
(cc, c') = fullAdd 60 (c, cd)
(cb, b') = fullAdd 60 (b, cc)
a' = a + cb
(ch, h') = fullAdd 1000 (h, i)
(cg, g') = fullAdd 60 (g, ch)
(cf, f') = fullAdd 60 (f, cg)
e' = e + cf
in TT a' b' c' d' e' f' g' h'
fullAdd :: Integer -> (Integer,Integer) -> (Integer,Integer)
fullAdd i (a,b) =
let x = a + b
in (x `div` i, x `mod` i)
阅读(1506) | 评论(0) | 转发(0) |