# -*- coding: UTF-8 -*-
'''
【程序68】
题目:有n个整数,使其前面各数顺序向后移m个位置,最后m个数变成最前面的m个数
1.程序分析:
2.程序源代码:
'''
if __name__ == '__main__':
n = int(input('the total number is:\n'))
m = int(input('back m:\n'))
def move(array,n,m):
array_end = array[n - 1]
for i in range(n - 1,-1,- 1):
array[i] = array[i - 1]
array[0] = array_end
m -= 1
if m > 0:move(array,n,m)
number = []
for i in range(n):
number.append(int(input('input a number:\n')))
print ('orignal number:',number)
move(number,n,m)
print ('after moved:',number)
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