用.net 存储img字段

如何将blob数据存入或取出数据库?用.net之后,就显得很方便,和很直接

...
byte[] content = ReadBitmap2ByteArray(fileName);
StoreBlob2DataBase(content);
...
protected static byte[] ReadBitmap2ByteArray(string fileName)
{
  using(Bitmap image = new Bitmap(fileName))
  {
    MemoryStream stream = new MemoryStream();
    image.Save(stream, System.Drawing.Imaging.ImageFormat.Bmp);
    return stream.ToArray();
  }
}

protected static void StoreBlob2DataBase(byte[] content)
{
   SqlConnection con = Connection;
   con.Open();
   try
   {
     // insert new entry into table
     SqlCommand insert = new SqlCommand(
     "insert into Images ([stream]) values (@image)",con);
     SqlParameter imageParameter =
     insert.Parameters.Add("@image", SqlDbType.Binary);
     imageParameter.Value = content;
     imageParameter.Size  = content.Length;
     insert.ExecuteNonQuery();
   }
   finally
   {
      con.Close();
   }
}

-------------------------------------------------------------------------------

protected static void StoreBlob2DataBaseOleDb(byte[] content)
{
   try
   {
      using(OleDbConnection con = Connection)
      {
         con.Open();

         // insert new entry into table
         using(OleDbCommand insert = new OleDbCommand(
             "insert into Images ([stream]) values (?)",con))
         {
            OleDbParameter imageParameter =
            insert.Parameters.Add("@image", OleDbType.Binary);
            imageParameter.Value = content;
            imageParameter.Size  = content.Length;
            insert.ExecuteNonQuery();
         }
      }
   }
   catch(Exception ex)
   {
      // some exception processing
   }
}

-----------------------------------------------------------------------------

// get image
 DataRowView drv = (DataRowView) _cm.Current;
 byte[] content = (byte[])drv["stream"];
 MemoryStream stream = new MemoryStream(content);
 Bitmap image = new Bitmap(stream);
 
 ShowImageForm f = new ShowImageForm();
 f._viewer.Image = image;
 f.ShowDialog(this);