2011-07-06 0:38:40 copy file 192.168.1.67 speed: 2.256 MBps
2011-07-06 1:30:46 copy file 192.168.1.67 speed: 2.000 MBps
2011-07-06 2:30:43 copy file 192.168.1.67 speed: 2.095 MBps
2011-07-07 0:33:43 copy file 192.168.1.67 speed: 2.146 MBps
2011-07-07 1:30:43 copy file 192.168.1.67 speed: 2.095 MBps
2011-07-07 2:30:43 copy file 192.168.1.67 speed: 2.146 MBps
2011-07-07 2:32:55 copy file 192.168.1.67 speed: 5.126 MBps
2011-07-08 0:31:01 copy file 192.168.1.67 speed: 1.508 MBps
2011-07-08 1:32:51 copy file 192.168.1.67 speed: 1.816 MBps
2011-07-09 0:32:44 copy file 192.168.1.67 speed: 2.119 MBps
2011-07-09 1:34:48 copy file 192.168.1.67 speed: 1.935 MBps
2011-07-09 2:30:57 copy file 192.168.1.67 speed: 1.618 MBps
2011-07-09 6:05:57 copy file 192.168.1.67 speed: 1.358 MBps
2011-07-09 8:30:57 copy file 192.168.1.67 speed: 1.618 MBps
2011-07-10 0:30:55 copy file 192.168.1.67 speed: 1.679 MBps
2011-07-10 1:31:00 copy file 192.168.1.67 speed: 1.534 MBps
可能看着有点眼花,就是说如何提取每天的第一行数据或最后一行数据,红色就是第一行,蓝色就是最后一行。
数组解法:
- # 只提取每天的第一行数据
-
awk '!a[$1]++' file
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awk '++a[$1]==1' file
-
-
# 只提取每天的最后一行数据
-
awk '{a[$1]=$0}END{for(i=1;i<=asort(a);i++)print a[i]}' file
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awk '!a[$1]++&&i{print i}{i=$0}END{print i}' file
非数组解法:
- # 只提取每天第一行数据
-
awk '$1!=x{x=$1;print}' file
-
-
# 只提取每天最后一行数据
-
awk 'NR>1{if($1!=x)print y}{x=$1;y=$0}' file <(echo)
话说数组的效率那确实在大文件下够慢的,别看非数组的命令比较长点,效率那可是高的。
sed解法:
- # 只提取每天第一行数据
-
sed -r ':a;$!N;s/([^ ]+)( +[^\n]+)\n\1.*/\1\2/;ta;P;D' file
-
-
# 只提取每天最后一行数据
-
sed -r ':a;$!N;s/([^ ]+) +[^\n]+\n\1(.*)/\1\2/;ta;P;D' file
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sed -r '$!N;/([^ ]+ ).*\n\1/!P;D' file
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