扩展的欧几里得算法:
给定两个正整数m和n,我们计算它们的最大公因子d和两个整数a和b,使得a*m + b*n = d。
算法代码如下所示:
#include <stdio.h>
int main() { int m, n, a, b, c, d, t; int ap, bp; int q, r;
scanf("%d %d", &m, &n);
ap = b = 1; a = bp = 0; c = m; d = n;
while (d != 0) { q = c / d; r = c % d;
c = d; d = r; t = ap; ap = a; a = t - q * a; t = bp; bp = b; b = t - q * b; }
printf("(%d) * %d + (%d) * %d = %d\n", ap, m, bp, n, c);
return 0; }
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