使用递归进行多进制输出

    下面代码是使用递归的方式进行多进制的输出:

 

#include <iostream>
using namespace std;

void displayInBase(int n, int base)
{
    if (n > 0)
    {
        displayInBase(n/base, base);
        cout << n % base;
    }
}

int main()
{
    int number, base;
    cout << "Input number and base: ";
    cin >> number >> base;
    if (base >= 2 && base <= 10)
    {
        cout << " " << number << "(base 10) = ";
        displayInBase(number, base);
        cout << "(base " << base << ")" << endl;
    }
    else
    {
        cout << "The base shoud be [2,10]" << endl;
    }
    return 0;
}