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分类: Mysql/postgreSQL

2010-01-16 17:02:24

Student(S#,Sname,Sage,Ssex) 学生表
Course(C#,Cname,T#) 课程表
SC(S#,C#,score) 成绩表
Teacher(T#,Tname) 教师表

问题:
1、查询“001”课程比“002”课程成绩高的所有学生的学号;
 
select a.S# from (select s#,score from SC where C#='001') a,(select s#,score
 
from SC where C#='002') b
 
where a.score>b.score and a.s#=b.s#;
2、查询平均成绩大于60分的同学的学号和平均成绩;
   
select S#,avg(score)
   
from sc
   
group by S# having avg(score) >60;
3、查询所有同学的学号、姓名、选课数、总成绩;
 
select Student.S#,Student.Sname,count(SC.C#),sum(score)
 
from Student left Outer join SC on Student.S#=SC.S#
 
group by Student.S#,Sname
4、查询姓“李”的老师的个数;
 
select count(distinct(Tname))
 
from Teacher
 
where Tname like '李%';
5、查询没学过“叶平”老师课的同学的学号、姓名;
   
select Student.S#,Student.Sname
   
from Student 
   
where S# not in (select distinct( SC.S#) from SC,Course,Teacher where  SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='叶平');
6、查询学过“001”并且也学过编号“002”课程的同学的学号、姓名;
 
select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#='001'and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002');
7、查询学过“叶平”老师所教的所有课的同学的学号、姓名;
 
select S#,Sname
 
from Student
 
where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='叶平' group by S# having count(SC.C#)=(select count(C#) from Course,Teacher  where Teacher.T#=Course.T# and Tname='叶平'));
8、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名;
 
Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2
 
from Student,SC where Student.S#=SC.S# and C#='001') S_2 where score2 <score;
9、查询所有课程成绩小于60分的同学的学号、姓名;
 
select S#,Sname
 
from Student
 
where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and score>60);
10、查询没有学全所有课的同学的学号、姓名;
   
select Student.S#,Student.Sname
   
from Student,SC
   
where Student.S#=SC.S# group by  Student.S#,Student.Sname having count(C#) <(select count(C#) from Course);
11、查询至少有一门课与学号为“1001”的同学所学相同的同学的学号和姓名;
   
select S#,Sname from Student,SC where Student.S#=SC.S# and C# in select C# from SC where S#='1001';
12、查询至少学过学号为“001”同学所有一门课的其他同学学号和姓名;
   
select distinct SC.S#,Sname
   
from Student,SC
   
where Student.S#=SC.S# and C# in (select C# from SC where S#='001');
13、把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩;
   
update SC set score=(select avg(SC_2.score)
   
from SC SC_2
   
where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname='叶平');
14、查询和“1002”号的同学学习的课程完全相同的其他同学学号和姓名;
   
select S# from SC where C# in (select C# from SC where S#='1002')
   
group by S# having count(*)=(select count(*) from SC where S#='1002');
15、删除学习“叶平”老师课的SC表记录;
    Delect SC
   
from course ,Teacher 
   
where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='叶平';
16、向SC表中插入一些记录,这些记录要求符合以下条件:没有上过编号“003”课程的同学学号、2
    号课的平均成绩;
   
Insert SC select S#,'002',(Select avg(score)
   
from SC where C#='002') from Student where S# not in (Select S# from SC where C#='002');
17、按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩,按如下形式显示: 学生ID,,数据库,企业管理,英语,有效课程数,有效平均分
   
SELECT S# as 学生ID
        ,(
SELECT score FROM SC WHERE SC.S#=t.S# AND C#='004') AS 数据库
        ,(
SELECT score FROM SC WHERE SC.S#=t.S# AND C#='001') AS 企业管理
        ,(
SELECT score FROM SC WHERE SC.S#=t.S# AND C#='006') AS 英语
        ,
COUNT(*) AS 有效课程数, AVG(t.score) AS 平均成绩
   
FROM SC AS t
   
GROUP BY S#
   
ORDER BY avg(t.score) 
18、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分
   
SELECT L.C# As 课程ID,L.score AS 最高分,R.score AS 最低分
   
FROM SC L ,SC AS R
   
WHERE L.C# = R.C# and
        L.score
= (SELECT MAX(IL.score)
                     
FROM SC AS IL,Student AS IM
                     
WHERE L.C# = IL.C# and IM.S#=IL.S#
                     
GROUP BY IL.C#)
       
AND
        R.Score
= (SELECT MIN(IR.score)
                     
FROM SC AS IR
                     
WHERE R.C# = IR.C#
                 
GROUP BY IR.C#
                    );
19、按各科平均成绩从低到高和及格率的百分数从高到低顺序
   
SELECT t.C# AS 课程号,max(course.Cname)AS 课程名,isnull(AVG(score),0) AS 平均成绩
        ,
100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分数
   
FROM SC T,Course
   
where t.C#=course.C#
   
GROUP BY t.C#
   
ORDER BY 100 * SUM(CASE WHEN  isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC
20、查询如下课程平均成绩和及格率的百分数(用"1行"显示): 企业管理(001),马克思(002),OO&UML (003),数据库(004
   
SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS 企业管理平均分
        ,
100 * SUM(CASE WHEN C# = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' THEN 1 ELSE 0 END) AS 企业管理及格百分数
        ,
SUM(CASE WHEN C# = '002' THEN score ELSE 0 END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS 马克思平均分
        ,
100 * SUM(CASE WHEN C# = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' THEN 1 ELSE 0 END) AS 马克思及格百分数
        ,
SUM(CASE WHEN C# = '003' THEN score ELSE 0 END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS UML平均分
        ,
100 * SUM(CASE WHEN C# = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' THEN 1 ELSE 0 END) AS UML及格百分数
        ,
SUM(CASE WHEN C# = '004' THEN score ELSE 0 END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS 数据库平均分
        ,
100 * SUM(CASE WHEN C# = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' THEN 1 ELSE 0 END) AS 数据库及格百分数
 
FROM SC
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