排名前5的SQL悲剧中肯定有:
delete from table t /* where true */;
update t set col='new_value' /* where true */
由于漏掉where条件或者拼接SQL后的where条件部分为true,这时整个表都被删除/更新了...
在使用mysql的应用中,避免此类低级错误的方法:
1、应用仔细检查(小心才能使得万年船啊~)
2、开启sql_safe_updates
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mysql> set sql_safe_updates=1;
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Query OK, 0 rows affected (0.00 sec)
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mysql> delete from t;
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ERROR 1175 (HY000): You are using safe update mode and you tried to update a table without a WHERE that uses a KEY column
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mysql> delete from t where 1=1;
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ERROR 1175 (HY000): You are using safe update mode and you tried to update a table without a WHERE that uses a KEY column
本文根据mysql源码介绍一下sql_safe_updates的逻辑
sql_safe_update开启后,mysql server层在调用mysql_update/mysql_delete时对where和limit进行判断后决定是否执行,代码调用关系:
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dispatch_command
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|->mysql_parse
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|->mysql_execute_command
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->mysql_update/mysql_delete
mysql_update:(sql/sql_update.cc)
当where条件中column没有索引可用且无limit限制时会拒绝更新
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/* If running in safe sql mode, don't allow updates without keys */
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if (table->quick_keys.is_clear_all())
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{
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thd->server_status|=SERVER_QUERY_NO_INDEX_USED;
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if (safe_update && !using_limit)
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{
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my_message(ER_UPDATE_WITHOUT_KEY_IN_SAFE_MODE,
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ER(ER_UPDATE_WITHOUT_KEY_IN_SAFE_MODE), MYF(0));
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goto err;
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}
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}
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mysql_delete中:(sql/sql_delete.cc)
当where条件为常量或者为空,或者where条件中column没有索引可用且无limit限制时拒绝删除
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const_cond= (!conds || conds->const_item());
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safe_update=test(thd->variables.option_bits & OPTION_SAFE_UPDATES);
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if (safe_update && const_cond)
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{
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my_message(ER_UPDATE_WITHOUT_KEY_IN_SAFE_MODE,
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ER(ER_UPDATE_WITHOUT_KEY_IN_SAFE_MODE), MYF(0));
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DBUG_RETURN(TRUE);
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}
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-
...
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/* If running in safe sql mode, don't allow updates without keys */
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if (table->quick_keys.is_clear_all())
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{
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thd->server_status|=SERVER_QUERY_NO_INDEX_USED;
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if (safe_update && !using_limit)
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{
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delete select;
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free_underlaid_joins(thd, select_lex);
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my_message(ER_UPDATE_WITHOUT_KEY_IN_SAFE_MODE,
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ER(ER_UPDATE_WITHOUT_KEY_IN_SAFE_MODE), MYF(0));
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DBUG_RETURN(TRUE);
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}
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}
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PS: update在有limit时是可以执行更新的,而delete严格一些,只要where条件为常量或者为空是会被拒绝的,如:
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mysql> update t set str='hello' where 1=1 limit 1;
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Query OK, 0 rows affected (0.00 sec)
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mysql> delete from t where 1=1 limit 1;
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ERROR 1175 (HY000): You are using safe update mode and you tried to update a table without a WHERE that uses a KEY column
不知道这是基于怎样的考虑...
不过开启sql_safe_updates后,update和delete在修改数据时,如果不带limit,需要where条件可以走索引,否则会报错
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