Chinaunix首页 | 论坛 | 博客
  • 博客访问: 71842
  • 博文数量: 41
  • 博客积分: 1475
  • 博客等级: 上尉
  • 技术积分: 440
  • 用 户 组: 普通用户
  • 注册时间: 2009-03-27 22:49
文章分类
文章存档

2012年(8)

2011年(1)

2009年(32)

我的朋友
最近访客

分类:

2009-05-22 21:28:01

题目Curling up the cube

解题思路
<方法1> 实际上将一个立方体的六个面展开在平面上,只有11种方式。这样就可以将输入和这11种方式进 行比较。
<方法2> 让立方体在平面上滚动来模拟立方体的展开。滚动时可以采用DFS方式。
代码

/*
 *******************************************************************************
 *
 * Filename: 10024.cpp
 * Description:
 * Author: Ye Xiaofeng, yexfeng # gmail.com
 *
 *******************************************************************************
 */


#include <iostream>

using namespace std;

//
// Roll direction
//
enum {
    NORTH = 0,
    SOUTH = 1,
    WEST = 2,
    EAST = 3,
    NONE = 4,
};

//
// Cube face
//
enum {
    DOWN = 0,
    UP = 1,
    RIGHT = 2,
    LEFT = 3,
    FRONT = 4,
    BACK = 5,
};

struct Pos {
    int i;
    int j;
};

short board[6][6];
short ok_cube[6] = { 1, 1, 1, 1, 1, 1 };

void search(Pos *pos, int direction, short *cube);
void roll(short *cube, int direction);
int roll_east(short *cube);
int roll_west(short *cube);
int roll_north(short *cube);
int roll_south(short *cube);


int main(int argc, char **argv)
{
    int caseNum = 0;
    Pos first_pos = {-1, -1};
    short cube[6] = {0, 0, 0, 0, 0, 0};

    cin >> caseNum;
    for (; caseNum != 0; caseNum--) {
        for (int i = 0; i < 6; i++) {
            for (int j = 0; j < 6; j++) {
                cin >> board[i][j];
                if (board[i][j] != 0 && first_pos.i == -1) {
                    first_pos.i = i;
                    first_pos.j = j;
                }
            }
        }

        // put cube on the first pos
        cube[DOWN] = 1;
        board[first_pos.i][first_pos.j] = 2;

        search(&first_pos, NONE, cube);
        if (0 == memcmp(ok_cube, cube, sizeof(cube))) {
            cout << "correct" << endl;
        } else {
            cout << "incorrect" << endl;
        }

        if (caseNum > 1) {
            cout << endl;
        }
        first_pos.i = -1;
        first_pos.j = -1;
        memset(cube, 0, sizeof(cube));
    }
}

void search(Pos *pos, int direction, short *cube)
{
    // mark the pos has been visited
    board[pos->i][pos->j] = 2;

    // roll west
    if (pos->j > 0 && board[pos->i][pos->j-1] == 1) {
        pos->j--;
        roll_west(cube);
        search(pos, EAST, cube);
        pos->j++;
    }


    // roll east
    if (pos->j < 5 && board[pos->i][pos->j+1] == 1) {
        pos->j++;
        roll_east(cube);
        search(pos, WEST, cube);
        pos->j--;
    }

    // roll north
    if (pos->i > 0 && board[pos->i-1][pos->j] == 1) {
        pos->i--;
        roll_north(cube);
        search(pos, SOUTH, cube);
        pos->i++;
    }

    // roll south
    if (pos->i < 5 && board[pos->i+1][pos->j] == 1) {
        pos->i++;
        roll_south(cube);
        search(pos, NORTH, cube);
        pos->i--;
    }

    roll(cube, direction);
}

void roll(short *cube, int direction)
{
    switch (direction) {
    case NORTH:
        roll_north(cube);
        break;
    case SOUTH:
        roll_south(cube);
        break;
    case WEST:
        roll_west(cube);
        break;
    case EAST:
        roll_east(cube);
        break;
    case NONE:
        break;
    }
}

int roll_east(short *cube)
{
    cube[RIGHT] = cube[UP];
    cube[UP] = cube[LEFT];
    cube[LEFT] = cube[DOWN];
    cube[DOWN] = 1;
    return 0;
}

int roll_west(short *cube)
{
    cube[LEFT] = cube[UP];
    cube[UP] = cube[RIGHT];
    cube[RIGHT] = cube[DOWN];
    cube[DOWN] = 1;
    return 0;
}

int roll_south(short *cube)
{
    cube[FRONT] = cube[UP];
    cube[UP] = cube[BACK];
    cube[BACK] = cube[DOWN];
    cube[DOWN] = 1;
    return 0;
}

int roll_north(short *cube)
{
    cube[BACK] = cube[UP];
    cube[UP] = cube[FRONT];
    cube[FRONT] = cube[DOWN];
    cube[DOWN] = 1;
    return 0;
}

阅读(989) | 评论(0) | 转发(0) |
给主人留下些什么吧!~~